Optimal. Leaf size=176 \[ \frac{10 c^{11/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{231 b^{9/4} \sqrt{b x^2+c x^4}}+\frac{20 c^2 \sqrt{b x^2+c x^4}}{231 b^2 x^{5/2}}-\frac{4 c \sqrt{b x^2+c x^4}}{77 b x^{9/2}}-\frac{2 \sqrt{b x^2+c x^4}}{11 x^{13/2}} \]
[Out]
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Rubi [A] time = 0.453419, antiderivative size = 176, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238 \[ \frac{10 c^{11/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{231 b^{9/4} \sqrt{b x^2+c x^4}}+\frac{20 c^2 \sqrt{b x^2+c x^4}}{231 b^2 x^{5/2}}-\frac{4 c \sqrt{b x^2+c x^4}}{77 b x^{9/2}}-\frac{2 \sqrt{b x^2+c x^4}}{11 x^{13/2}} \]
Antiderivative was successfully verified.
[In] Int[Sqrt[b*x^2 + c*x^4]/x^(15/2),x]
[Out]
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Rubi in Sympy [A] time = 41.2058, size = 168, normalized size = 0.95 \[ - \frac{2 \sqrt{b x^{2} + c x^{4}}}{11 x^{\frac{13}{2}}} - \frac{4 c \sqrt{b x^{2} + c x^{4}}}{77 b x^{\frac{9}{2}}} + \frac{20 c^{2} \sqrt{b x^{2} + c x^{4}}}{231 b^{2} x^{\frac{5}{2}}} + \frac{10 c^{\frac{11}{4}} \sqrt{\frac{b + c x^{2}}{\left (\sqrt{b} + \sqrt{c} x\right )^{2}}} \left (\sqrt{b} + \sqrt{c} x\right ) \sqrt{b x^{2} + c x^{4}} F\left (2 \operatorname{atan}{\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}} \right )}\middle | \frac{1}{2}\right )}{231 b^{\frac{9}{4}} x \left (b + c x^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((c*x**4+b*x**2)**(1/2)/x**(15/2),x)
[Out]
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Mathematica [C] time = 0.515758, size = 133, normalized size = 0.76 \[ \frac{1}{231} \sqrt{x^2 \left (b+c x^2\right )} \left (\frac{2 \left (-21 b^2-6 b c x^2+10 c^2 x^4\right )}{b^2 x^{13/2}}+\frac{20 i c^3 \sqrt{\frac{b}{c x^2}+1} F\left (\left .i \sinh ^{-1}\left (\frac{\sqrt{\frac{i \sqrt{b}}{\sqrt{c}}}}{\sqrt{x}}\right )\right |-1\right )}{b^2 \sqrt{\frac{i \sqrt{b}}{\sqrt{c}}} \left (b+c x^2\right )}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[Sqrt[b*x^2 + c*x^4]/x^(15/2),x]
[Out]
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Maple [A] time = 0.04, size = 156, normalized size = 0.9 \[{\frac{2}{ \left ( 231\,c{x}^{2}+231\,b \right ){b}^{2}}\sqrt{c{x}^{4}+b{x}^{2}} \left ( 5\,\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) \sqrt{-bc}\sqrt{2}{x}^{5}{c}^{2}+10\,{c}^{3}{x}^{6}+4\,b{c}^{2}{x}^{4}-27\,{b}^{2}c{x}^{2}-21\,{b}^{3} \right ){x}^{-{\frac{13}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((c*x^4+b*x^2)^(1/2)/x^(15/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\sqrt{c x^{4} + b x^{2}}}{x^{\frac{15}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^4 + b*x^2)/x^(15/2),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{\sqrt{c x^{4} + b x^{2}}}{x^{\frac{15}{2}}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^4 + b*x^2)/x^(15/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x**4+b*x**2)**(1/2)/x**(15/2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\sqrt{c x^{4} + b x^{2}}}{x^{\frac{15}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(c*x^4 + b*x^2)/x^(15/2),x, algorithm="giac")
[Out]